Remove List Of Phrases From String
I have an array of phrases: bannedWords = ['hi', 'hi you', 'hello', 'and you'] I want to take a sentence like 'hi, how are tim and you doing' and get this: ', how are tim doing'
Solution 1:
Since you want to remove extra spaces as well, the regex below should work better:
s = "Hi, How are Tim and you doing"
bannedWords = ['hi', 'hi you', 'hello', 'and you']
for i in bannedWords:
s = re.sub(i + "\s*", '', s, flags = re.I)
print s
# ', How are Tim doing'
Solution 2:
You can use re.sub
with a flag to do this in a case insensitive manner.
import re
bannedWords = ['hi', 'hi you', 'hello', 'and you']
sentence = "Hi, how are Tim and you doing"
new_sentence = re.sub('|'.join(bannedWords) + r'\s+', '', sentence, flags=re.I)
# new_sentence: ", how are Tim doing"
Solution 3:
With regex you can join words you want to remove with |. We also want to remove any multiple blankspace with one blankspace. This ensures we only do two operations.
import re
defremove_banned(s,words):
pattern = '|'.join(words)
s = re.sub(pattern, '', s, flags = re.I) # remove words
s = re.sub('\s+', ' ', s, flags = re.I) # remove extra blank space'return s
bannedWords = ['hi', 'hi you', 'hello', 'and you']
s = "Hi, How are Tim and you doing"print(remove_banned(s,bannedWords))
Returns:
, How are Tim doing
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