Selecting Only Max Value In Python List Of Dicts

I have a list of dicts as follows: [{'server':'8.8.8.8', 'domains':[{'google.com':[{'time':15, 'serial':14}, {'time':78, 'serial':14}]}, {'intuit.com':[{'time':20,

Solution 1:

The solution using built-in max() function:

import json

# l is your initial list of dictsfor item in l:
    for d in item['domains']:
        for k, v in d.items():
            # whether `serial` numbers are unique 
            has_uniq_serial = len(set([i['serial'] for i in v])) > 1
            d[k] = max(v, key=lambda o: o['serial']) if has_uniq_serial elsemax(v, key=lambda o: o['time'])

# `json.dumps` used for pretty printing of nested dictsprint(json.dumps(l, indent=4))

The output:

[{"server":"8.8.8.8","domains":[{"google.com":{"serial":14,"time":78}},{"intuit.com":{"serial":23,"time":20}}]},{"server":"8.8.4.4","domains":[{"google.com":{"serial":76,"time":92}},{"intuit.com":{"serial":89,"time":45}}]},{"server":"206.67.222.222","domains":[{"google.com":{"serial":76,"time":98}},{"intuit.com":{"serial":59,"time":65}}]}]

Solution 2:

Try this (d is your dict):

for item in d:
    for i in item["domains"]:
        for k, v in i.items():
            c = sorted([(j["time"], j["serial"]) for j in v], key=lambda x: (x[1], x[0]))
            i[k] = {"time": c[-1][0], "serial": c[-1][1]}

print d

Solution 3:

You can sort your time-serial list for each domain by your requirement and get the first one, let variable data be your input list:

defdomain_sorter(d):
    defcompare(x, y):
        k = y['serial'] - x['serial']
        j = y['time'] - x['time']

        return k if k != 0else j
    returnsorted(d, cmp=compare)

deffilter_domain(domain):
    for k, v in domain.items():
        return {
            k: domain_sorter(v)[0]
        }

print [{
    "server": e['server'],
    "domains": [filter_domain(domain) for domain in e['domains']]
} for e in data]